Suppose a proton is moving with a speed of 10 m/s in a direction parallel to a uniform magnetic field of 3.0 T. What is the magnitude and direction of the magnetic force on the proton

the magnetic force on the proton is zero.

Explanation:

Given;

speed of the proton, v = 10 m/s

magnitude of the magnetic field, B = 3 T

The magnitude of the magnetic force on the particle is calculated as;

F = qvBsinθ

where;

θ is the angle between the velocity of the particle and the magnetic field

Since the particle is moving parallel to the magnetic field, θ = 0

F = qvBsin(0)

F = 0

Therefore, the magnetic force on the proton is zero.

This is a trick question, in that the numbers do not matter.

Study the dependence of the magnetic force on the direction of the magnetic field and the direction of motion of the particle. When is it a maximum? When is it a minimum?

Hint: In vector notation, this is often expressed as q v x B, where q is the electric charge of the particle, v is its velocity (a vector), and B is the magnetic field vector.

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