The bird perched on the swing in the figure has a mass of 56 g, and the base of the swing
has a mass of 179.2 g. Assume that the swing
and the bird are originally at rest and that the
bird then takes off horizontally at 2.38 m/s.
The acceleration of gravity is 9.8 m/s^2

If the base can swing freely (without friction) around the pivot, how high will the base
of the swing rise above its original level?
Answer in units of m.

Edit the post so i can see the letters for each answer, and increase the points required so i'd be able to answer it.

Uncle grandma

Since you have not included the experiment situation and the data, of course, i can not give you specific details about it. but i can you with this question.1) i will assume that the motion is projectile (parabolic) motion.2) yes, the horizontal distance depends on the horizontal velocity as, naming vx the horizontal velocity and t the time, it is: x = vx × t3) now, observe that the flight time depends on the vertical velocity as, naming voy the initial vertical velocity, t the time and y the vertical distance before reaching the ground: y = yo + voy×t - gt² / 2.the higher the initial vertical velocity (voy) the longer the object will be flying and so t will be higher in the equation for the horizontal distance.that explains the relationship between the horizontal distance and the horizontal velocity.

Sound wavelength of visible light waves