A hot cube of iron was heated up using 1500 J of thermal energy and was placed in a beaker of water. Before it was heated, the iron cube was 20.0 ˚C. The cube of iron raised the temperature of the water to 45.0 ˚C. If the iron cube has a mass of 133 g, what is the specific heat capacity of iron?

451.13 J/kg.°C

Explanation:

Applying,

Q = cm(t₂-t₁) Equation 1

Where Q = Heat, c = specific heat capacity of iron, m = mass of iron, t₂= Final temperature, t₁ = initial temperature.

Make c the subject of the equation

c = Q/m(t₂-t₁) Equation 2

From the question,

Given: Q = 1500 J, m = 133 g = 0.113 kg, t₁ = 20 °C, t₂ = 45 °C

Substitute these values into equation 2

c = 1500/[0.133(45-20)]

c = 1500/(0.133×25)

c = 1500/3.325

c = 451.13 J/kg.°C

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