Physics
Physics, 04.06.2021 21:40, marrizza7

An electron in a hydrogen atom drops from the n = 4 (-0.85 eV) to the n = 3 (-1.51 eV) state. What is the energy of the emitted radiation?
1. -2.36 eV
2. 0.66 eV
3. -0.66 eV
4. 2.36 eV

answer
Answers: 1

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An electron in a hydrogen atom drops from the n = 4 (-0.85 eV) to the n = 3 (-1.51 eV) state. What...

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