A 8.25-N force is applied to a 2.50 kg object to accelerate it rightwards. The object encounters 2.19 N of friction. Determine the acceleration of the object. (Neglect air
resistance.)

Explanation:

Use F - f = ma since we are on a flat surface. We are given the applied Force as 8.25, the frictional force as 2.19, and a mass of 2.50. Filling in:

8.25 - 2.19 = 2.50a. Doing the subtraction on the left gives us:

6.06 = 2.50a and we divide to 3 sig figs to get

a = 2.42 m/s/s

yo yo yo its papaguy in the house lol

okay, ima .

um it shows links to uh so kinda microsoft website is that were ima go or no? ?

when jerome paddle in flowing river towards east the net speed of jerome will increase

so the net speed of jerome will be given as

now the speed of paul will be same as it is given as he is running on the ground

so

so here we can say since the speed of jerome is more so he will win the race

now as we know the distance so the time difference is given as

so jerome will reach first and the time difference will be 203.55 s or 3.4 min