Un cuerpo con un peso de magnitud igual a 200 N cuelga sobre dos cuerdas que forman un ángulo de 140° entre ellas. Determina la magnitud de la fuerza que ejerce cada cuerda sobre el cuerpo.

T = 292.4 N

Explanation:

For this exercise we must use the translational equilibrium condition

         ∑ F = 0

Since force is a vector magnitude, the easiest way

Since the angle between the two forces is 140, the angle from the vertical is half tea = 70

        cos θ = T_y / T

        sin θ = Tₓ / T

        T_y = T cos 70

        Tₓ = T sin 70

X axis

        Tₓ₁-Tₓ₂ = 0

        Tₓ₁ = Tₓ₂

Y axis  

        T_y + T_y - W = 0

        2 T cos 70 = W

        T =

let's calculate

        T = 200/2 cos 70

        T = 292.4 N

ok

explanation:

when two balls of the different masses are dropped from equal height, they reach the ground at the same time .this is because they experience the same acceleration.

the acceleration is independent of mass.

thus when they are dropped they will always maintain the same velocity and travel the same distance (neglect air resistance of course) at the same time.