A force F1 of magnitude 6.00 units acts on an object at the origin in a direction theata=30 degrees above the positive x-axis. A second force F2 of magnitude 5.00 units acts on the object in the direction of the positive y-axis. Required:
Find graphically the magnitude and direction of the resultant force F1+F2.

at positions a, g kinetic energy is maximum.

at position d, potential energy is maximum.

we have been given a quadratic function and we need to restrict the domain such that it becomes a one to one function.

we know that vertex of this quadratic function occurs at (5,2).

further, we know that range of this function is .

if we restrict the domain of this function to either or , it will become one to one function.

let us know find its inverse.

upon interchanging x and y, we get:

let us now solve this function for y.

hence, the inverse function would be if we restrict the domain of original function to and the inverse function would be if we restrict the domain to .