An electron travels at horizontal velocity 5*10^6m/s in a vacuum between two charged plates 100 mm long and am apart, to which a p. d. of 30 V is applied. The charge on
dectron is 1.5 10 C and the mass of an electron is
1x 10 kg
What size force will the electron experience while it passes
through the plates?
What acceleration will this give to the electron
If the positive plate is the lower one, in which direction will
the electron accelerate?
d) How long will it take for the electron to pass through the
plates​

An atom's smaller negative particles are at a distance from the central positive particles, so the negative particles are easier to move. 

Answerthe energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.explanationwe define electric potential as the ratio electric potential energy to the charge,    then the following gives us the potential difference,      the formula  may be on your formula sheet.the change in electric potential energy would be the energy that would needed to move it from point a to point b. solving for that, we get    using q = 8.00  × 10⁻¹⁹ c and  δv = 2.00 v, we get    the energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.