One 4 kg bowling ball traveling right at 1 m/s collides with a stationary 2 kg bowling ball. They stick together and move away. What is the final velocity of the two bowling balls stuck together?

0.6m/s

Explanation:

Given data

M1= 4kg

U1= 1m/s

M2= 2kg

U2= 0m/s

The system experiences an inelastic collision, the expression for inelastic collision is

M1U1+ M2U1= (M1+M2)V

Subsitute

4*1+ 2*0= (4+2)*V

4+0= 6V

4=6V

V= 4/6

V= 0.6m/s

Hence the common velocity is 0.6m/s

another example of kinetic energy would be,

kinetic energy   >     moving energy

answer   >   letter choice (c),   a hammer falling off a table.

hope that !                                         : )

this is an example of "committed" time.

committed time, as contracted time, takes need over essential and available time since it is seen as profitable work. it alludes to the time allotted to keep up a home and family. at the point when a man is commuting using committed time this individual may feel that the drive is an obligation to family, for example, strolling youngsters to class or driving a mate to work. contracted and committed time clients may feel that their commute could really compare to the commute of important or leisure time clients on the grounds that their commute is profitable work. in this manner, they might be more disposed to pick a mechanized method of movement.