Students were asked to design a lab that would illustrate a concept that they had learned about during the semester. Which student designed the
lab in the diagram?
Lamp
Ice Cubes
Glass Cover
Water Droplets
Water
OA. Student 3 designed a lab to illustrate the phases of the moon
where the lamp represents the Sun and the ice cubes
represent the phases of the Moon.
o
B.
Student 2 designed a lab to illustrate convection currents where
the lamp represents the sun and the ice cubes represent the
uneven heating of the Earth.
Student 4 designed a lab to illustrate the solar system where the
lamp represents the Sun and the ice cubes represent the
planets.
C.
D.
Student 1 designed a lab to illustrate the water cycle where the
lamp represents the sun's energy and the ice cubes
represent condensation.

I think that the answer would be D.Given the diagram if you just see you will find that a lamp is projected in such a way that its light falls on the ice cubes so the ice would get a large magnitude of heat energy so the kinetic energy of the molecules increases and at a constant temperature(0°c) they would melt and gets transformed into tiny water doplets as we know if the light is continuous enabled on water droplets then at a certain time it would change into water vapours as we know that if any liquid gets evaporated up then it will only evaporate when it absorbs heat from its surrounding as doing so the surrounding along with glass box would get cool down and so the water vapours on air would also cool down and get condensed on outer glass box particles and if the glass box is porous in nature then the water droplets would fill the box

Hope it helps

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s