Magnetic resonance imaging often need magnetic fields of a strength of around 1.50 T. The solenoid is 1.80 meters long and 75.0 cm in diameter. It is tightly wound with a single layer of 2.00 mm diameter superconducting wire. Required:
What current is needed?

The current needed is 2387.32 A

Explanation:

Given;

strength of the magnetic field, B = 1.5 T

length of the solenoid, L = 18 m

diameter of the solenoid, D = 75 cm = 0.75 m

diameter of the superconducting wire, d = 2 mm = 0.002 m

The number of turns of the solenoid is calculated as;

The magnetic field strength is given by;

Where;

I is the current needed

μ₀ is permeability of free space = 4π x 10⁻⁷ T.m/A

Therefore, the current needed is 2387.32 A

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1/0.14nm = 10^10/1.4 a lot