26. A physical science student is performing a thermodynamics experiment in the school laboratory. She takes a 30.0 g ice cube at 0. °C and melts it to water in a beaker over a laboratory burner. She then heats the water to boiling at 100. °C. Finally she boils the water entirely to steam at 100. °C. How much thermal energy was gained by the water during this entire process?

The thermal energy gained by the water during the entire process is 90,372 J

Explanation:

Given;

mass of the ice cube, m = 30 g

latent heat of fusion of ice, L = 334 J/g

specific heat capacity of water, C = 4.184 J/g⁰C

latent heat of vaporization of water, h = 2260 J/g

The thermal energy gained by the water during the entire process is calculated as;

The heat of fusion of the ice at 0⁰C is calculated as;

The heat of capacity of the water from  0⁰C to 100 ⁰C

The heat of vaporization of the steam at 100⁰C is calculated as;

The thermal energy gained by the water during the entire procees;

Qt = 10,020 J  +  12,552 J   +  67,800 J

     = 90,372 J

Therefore, the thermal energy gained by the water during the entire process is 90,372 J

the focus of lesson 1 is newton's first law of motion - sometimes referred to as the law of inertia. newton's first law of motion is often stated as. an object at rest stays at rest and an object in motion stays in motion with the same speed and in the same direction unless acted upon by an unbalanced force.

explanation:

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