Uf a 2Kilowatt electric immersion heater is used to warm 200kg of water of 20°, Calculate a) the quantity of heat energy given out by immersion heat is 2 hours time. b) final temperature of water.​

(a) the quantity of heat energy given out is 1.44 x 10⁷ J

(b) the final temperature of the water is 37.14 ⁰C

Explanation:

Given;

power supplied to the heater, P = 2 kW = 2,000 W

mass of water, m = 200 kg

duration of the power supply, t = 2 hours = 2 x 3600s = 7,200 s

initial temperature of the water, t₁ = 20° C

specific heat capacity of water, c = 4200 J/kgC

(a) the quantity of heat energy given out by immersion heat is 2 hours;

Q = P x t

Q = 2,000 W  x 7,200 s

Q = 1.44 x 10⁷ J

(b) the final temperature of water

Q = mcΔt

Δt = Q / mc

Δt = (1.44 x 10⁷) / (200 x 4200)

Δt = 17.14

Δt = t₂ - t₁

Δt + t₁ = t₂

17.14 + 20 = t₂

37.14 ⁰C = t₂

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explanation:

jupiter is the largest planet in our solar system, having a mass and radius that are respectively, 318 and 11.2 times that of earth. suppose that an object falls from rest near the surface of each planet and that the acceleration due to gravity remains constant during the fall. each object falls the same distance before striking the ground. determine the ratio of the time of fall on jupiter to that on earth.