A uniform metre rule is pivoted at its centre. A 20g mass is placed at the 10 cm mark and a 50g mass at the 40cm mark. At what mark must a second 50g mass be placed for the system to be in rotational balance?​

which statement about this sum is true? −245+2.7

i wanna say it’s between b and d, leaning more towards b.

we need to know the time interval during which the force acts. impulse of force = momentum change

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s