When a net force of 3 N is applied to a 0 75 kg cart the cart's velocity changes from 0.2 m/s to 18 m/s in 0.3s Suppose that by adding masses the total mass of the cart doubles the same force applied for the same amount of time what will the change in velocity be in m/s? plz help no links or bad answers I’m in a test;(

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explanation:

when two balls of the different masses are dropped from equal height, they reach the ground at the same time .this is because they experience the same acceleration.

the acceleration is independent of mass.

thus when they are dropped they will always maintain the same velocity and travel the same distance (neglect air resistance of course) at the same time.

t = 1/400 h   ⇔ 0.0025 h ⇔ 9s ⇔ 0.15 m

any of the answers are correct.