Part B Now check your hypothesis by investigating two Tracker videos: Ball Drop and Large Ball Drop.
Open the Tracker experimentBall Drop C. Watch the movie by clicking on the play button. (The other video controls allow you to "rewind" the
video or step forward or backward one frame at a time.). Watch the video to go ahead with the activity,
Now, keep the Ball Drop video open, and also open the Tracker experiment Large Ball Drop and watch that video.
For the Ball Drop experiment, observe the graph of the vertical displacement of the small ball against time (y vs. t). What can you say about the
vertical displacement of the small ball? What graph shape is this? What does this shape tell you about the mathematical relationship between y
and t?

    m₁v₁ + m₂v₂ = (m₁ + m₂)vmomentum is conserved.the left-hand side of the equation represents the momentum in the system before the collision.the right-hand side represents the momentum in the system after the collisionm₁ and v₁ represents the mass and the velocity of the physics blockm₂ and v₂ represents the mass and velocity of the ball of puttyv represents the final velocity of the combined mass.the question states the two masses stick together. they combined mass has its own velocity with the body mass the sum of the two objects' massestheir combined momentum is (m₁ + m₂)vto find the magitude of (m₁ + m₂)v, we need to add the vectors on the left-hand side of the equation: m₁v₁ + m₂v₂.note the diagram. i have positioned the vectors in accordance with their directions.the magnitude of the resultant can be calculated using the pythagorean theorem since this is a right triangle situation (north and west are perpendicular)|(m₁ + m₂)v| =  √[ (m₁v₁)² + (m₂v₂)² ]|(m₁ + m₂)v| =  √[ (1.5kg·8.0m/s)² + (0.40kg·20m/s)² ]|(m₁ + m₂)v| =  14.4 kg m/sfor two significant figures (assuming that 20m/s is two), this rounds to 14 kg m/s

The upward force acting on the wing of a airplane in flight is known as the "lift" force. (d)