Two charges create 8.00 N of electric force on each other. If you increase
their distance to twice its original
value, how much electric force do
they exert on each other?
(Hint: How does Fe change with distance?)
[?]N

2.00 (right on acellus)

Explanation:

doubling the distance between two charges makes F (8.00) quarter, so you would just do 8.00*1/4.

0 = 0.40 / 0 = 0

= 0.20 = 9.80 ⁄2 =?

=0 , = = 0.20 =0.50 0 0.40 ⁄

=0−122 =0−12(9.80 ⁄2)(0.50)2 =1.2