The rate at which charge passes through a 6 Ω resistor at a given point in time is 3 mA. How much charge passes through this resistor in 5 seconds?

Q = 0.015 Coulombs

Explanation:

Given the following data;

Resistance = 6 Ω

Current = 3 mA = 0.003 A

Time, t = 5 seconds

To find the quantity of charge passing through the resistor;

Mathematically, quantity of charge is given by the formula;

Quantity of charge, Q = current * time

Q = 0.003 * 5

Q = 0.015 Coulombs

2b2t

explanation:

2b2t