Physics, 11.05.2021 18:30, iop123456

A vehicle is travelling with uniform velocity along a straight, level stretch of highway. The combined force due to the rolling friction and air resistance is - 5000 N. What is the applied force on the vehicle as it moves?

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answered: jsotopalomino1016

The applied force on the vehicle is 5,000 N

Explanation:

From the question, we have the following parameters of the motion of the vehicle;

The form of the velocity with which the vehicle is travelling = Uniform velocity

The direction of motion of the vehicle = Along a straight and level stretch of the highway

The combined force which acts as resistance to the vehicle's motion = 5,000 N from rolling friction and resistance of the air opposite to the direction of motion

A vehicle travelling with uniform velocity has zero acceleration, therefore;

The acceleration of the vehicle, a = 0 m/s²

According to Newton's Second Law of Motion, we have;

Force, F = Mass, m × Acceleration, a

∴ The net force of acting on the vehicle, F = m × a

Where;

m = The mass of the vehicle

a = The acceleration of the vehicle = 0 m/s²

∴ F = m × 0 = 0

The net force on the vehicle = 0, therefore;

The applied force + The force of rolling friction and air resistance = 0

We therefore have;

The applied force + 5,000 N = 0

∴ The applied force = 0 - 5,000 N = -5,000 N

The applied force, F = 5,000 N in the direction of motion.

answered: Guest

Gas is all around us which means that the atmosphere

answered: Guest

russian is not my first language, so i'm afraid i can't write out an answer in russian, but hopefully you can find a way to do so. here's my best translation of the problem: you're given a plot of a particle's position in one-dimensional space over time, and you're asked to find either the total distance traveled by the particle after 6 seconds had elapsed, or the total displacement of the particle after 6 seconds.

if you want the total distance traveled, you would first need to determine the particle's velocity as a function of time, then integrate that over the 6-second interval. we know the position function is quadratic with roots at 0 and 6, so we have

$x(t)=ax(x-6)$

where $a$ is unknown. because the position is parabolic, there is symmetry about the midpoint at $t=3$ , and we know that

$x(3)=10\implies -9a=10\implies a=-\dfrac{10}9$

so that the position function is

$x(t)=-\dfrac{10}9x(x-6)$

which means the velocity is

$v(t)=\dfrac{\mathrm dx}{\mathrm dt}=-\dfrac{20}9x+\dfrac{60}9$

then the total distance traveled is

$\displaystyle\int_{t=0}^{t=6}|v(t)|\,\mathrm dt=\left\{\int_{t-0}^{t=3}-\int_{t=3}^{t=6}\right\}v(t)\,\mathrm dt=20$

so the total distance traveled is 20 m.

on the other hand, if you want to find displacement: the particle starts at $x=0$ and ends at $x=0$ , so its displacement is 0.

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A vehicle is travelling with uniform velocity along a straight, level stretch of highway. The combin...