A man is driving his 1100 kg car at 36 km/h on a straight freeway. After accelerating for 30 seconds, the car has a speed of 108 km/h. How much work did the engine do during the 30 seconds?

W = 439998 J = 439.99 KJ

Explanation:

First, we will calculate the acceleration of the car by using the first equation of motion:

where,

a = acceleration = ?

vf = final speed = = 30 m/s

vi = initial speed = = 10 m/s

t = time = 30 s

Therefore,

a = 0.67 m/s²

Now, we will calculate the force applied by the engine:

F = ma

where,

F = force = ?

m = mass = 1100 kg

Therefore,

F = (1100 kg)(0.67 m/s²)

F = 733.3 N

Now, we will calculate the distance covered by the car by using the second equation of motion:

s = 600 m

Now, the work done (W) by engine can be calculated as follows:

W = Fs

W = (733.3 N)(600 m)

W = 439998 J = 439.99 KJ

pe = weightxheight = 2000x1000=2,000,000joules

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