A horizontal force T of 100N is applied to a box of books of 20kg resting on a wooden table. Show that the box slides if the coefficient of friction of the box and the table is 0.40. If the box slides what is its acceleration? Normal force between the box and the table is mg= 196N​

1.08m/s^2

Explanation:

apply newton's second paw

100-0.4×20×9.8=20a

a=1.08k/s^2

a.) is the correct answer.

explanation:

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer