A body of mass 36 g moves with SHM of amplitude A = 13 cm and period T = 12 s. At time t=0 the displacement, x, is 13 cm. (a) Find the velocity when x = 5 cm. (b) Find the
force acting on the body when t = 2 s.

Ireally don’t know

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Answer: 1.4 seconds which is the third optionexplanation: current is defined as the flow of charge per timetherefore, the equation that relates current, charge and time can be expressed as follows: i = δq / δtwhere: i is the current given = 1.8 ampereδq is the charge given = 2.5 coulombδt is the time required for the flow of the given charges to give the 1.8 ampere.substitute with the givens in the above equation to get the time as follows: 1.8 = 2.5 / δtδt = 2.5 / 1.8 = 1.38888 which is approximately 1.4 secondshope this was !