Physics, 29.04.2021 06:30, queenkimm26

Consider the reaction below Na2CO3 (aq) + CaCl2 (aq) CaCO3 (s) + 2NaCl (aq) If the releases 39.4 kJ of energy, how many kilocalories does it release? (1 cal = 4.184 J) (Round off answer to 2 decimal place)

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Consider the reaction below Na2CO3 (aq) + CaCl2 (aq) CaCO3 (s) + 2NaCl (aq) If the releases 39.4 kJ...