PLEASE What is the magnetic force on a proton that is moving at 3.8 x 107m/s up through a magnetic field that is 0.72 T and pointing toward you? The charge on a proton is 1.6 x 10-19 C. Use F = qvx B sine.
A. 6.1 x 10-12 N right
B. 4.4 x 10-12 N left
C. 4.4 x 10-12 N right
D. 6.1 x 10-12 N left

Initial velocity,  u = 4.9 m/sfinal velocity = v m/sinitial height,  h₁ =  245 m    final height, h₂ = 0a = -9.8  m/s²time taken = t secondss = ut + 0.5at²⇒  (h₂-h₁) = ut + 0.5at²⇒  0-245 = 4.9t + 0.5×(-9.8)×t²⇒ -245 = 4.9t - 4.9t²⇒ 4.9t² -4.9t -245 =0solving it, we get   t = 7.59sv  = u +  at = 4.9 -9.8×7.59 = 4.9 - 74.38 = -69.48 m/svelocity is  69.48 m/s downward

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I'd go for the one that says that knees are fulcrums, lower legs are levers and the ankles hold loads.hope it ,happy homework/ study/ exam!