The math club is selling raffle tickets to raise money for the Fall Ball. The raffle tickets cost them $0.08 each at the office supply store and they spent $55 making t-shirts for the club members to wear. They are selling the raffle tickets for $2 each. If

x
represents the number of raffle tickets they sell, the following functions can be used to represent this situation where
()
C
(
x
)
is the club's costs and
()
R
(
x
)
is the amount of revenue they make selling the tickets.

()=0.08+55
C
(
x
)
=
0.08
x
+
55

()=2
R
(
x
)
=
2
x

Which of the following functions represent the profit,
(),
P
(
x
)
,
made by the math club during their raffle ticket sale?

Joe Mama Is your answer

Explanation:

i'm thinking more like energy

most voltage drop calculators want the distance between the source and destination. then internally, they double it so both the source and return wires are calculated. but you need to know which distance the calculator uses so you're not half of what you should be or double what you should be.

most circuit breakers will not take a #6 directly, so the electrician will have to splice on a smaller pigtail. you also have to upsize the grounding wire when you upsized the ungrounded (hot) wire (see note in 250.122). this will preclude using most cable assemblies, as a cable with #6 copper will most likely only have a #10 grounding conductor. you need a #6 grounding conductor if the circuit is 20a. a #8 cable is no better, as it will have a #10 grounding conductor too. but most 20a breakers will take a #8 directly.

in your related post, you didn't say what type of load this is. if it is a light or heater, voltage drop won't be a big issue. if this is a motor, the current needs are huge at startup and the voltage drop can pose a problem. if this is a motor, knowing if the motor is under much load during startup will answer the voltage drop effect (a saw is easier to start than a compressor).