Physics, 21.04.2021 16:30, torlajap017

You are a traffic accident investigator. You have arrived at the scene of an accident. Two trucks of equal mass (3,000 kg each) were involved in a rear-end accident at a stop sign. Here is what you know: Truck 1 started from rest at the top of a 22-meter hill and coasted toward the intersection.

Truck 2 was on a flat stretch of road at the bottom of the hill directly in front of Truck 1.
At the bottom of the hill, Truck 1 was going 20 m/s; Truck 2 was going 35 m/s.

There were no skid marks left by Truck 2. The collision occurred at the stop sign where Truck 2 had stopped.

After the collision, both trucks moved together in the same direction at 10 m/s before slowly rolling to a stop.

You must now push Truck 2, using 1,000 N of force, 8 meters off to the side of the road so no one else gets hurt.

1. What was the potential energy of Truck 1 at the top of the hill? (3 points)

3000 x 9.81 x 22 = 647,460 J

2. What was the kinetic energy of each truck before they began braking? (4 points)

Truck 1: 600,000 J
Truck 2: 1,837,500 J

3. A. How much energy did Truck 1 lose from the top to the bottom of the hill? (3 points)

47,460

B. Where do you suppose that energy went? (2 points)

I suppose that the energy converts into heat and sound that is felt during the crash.

4. How much work was done to bring Truck 2 to a stop? (4 points)
5. If Truck 2 came to a stop in 15 seconds, how much power (in watts) did it take to stop Truck 2 at the stop sign by applying force to the brakes? (3 points)

6. What is the final combined momentum of the trucks right after the accident? (6 points)

7. Assuming that there are no other nonconservative forces involved, what impulse was given to each truck during the collision? (6 points)

A. Truck 1: (3 points)

B. Truck 2: (3 points)

8. How much energy did Truck 1 lose in the collision? (3 points)

9. How much energy did Truck 2 gain in the collision? (3 points)

10. Which of the two laws covered in this unit - Law of Conservation of Momentum or Law of Conservation of Energy - is obeyed in this problem? Explain your reasoning. (5 points)

11. How much work did it take to move Truck 2 off to the side of the road? (3 points)

12. If it took you 40 seconds to move Truck 2 off the road, how much power did you expend? (3 points)

13. Which simple machine does a truck have that helped you move Truck 2? Explain. (2 points)

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answered: Guest

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answered: Guest

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answered: Guest

Acetic acid /əˈsiːtɪk/, systematically named ethanoic acid /ˌɛθəˈnoʊɪk/, is a colourless liquid organic compound with the chemical formula ch3cooh (also written as ch3co2h or c2h4o2). when undiluted, it is sometimes called glacial acetic acid. vinegar is no less than 4% acetic acid by volume, making acetic acid the main component of vinegar apart from water. acetic acid has a distinctive sour taste and pungent smell. in addition to household vinegar, it is mainly produced as a precursor to polyvinyl acetate and cellulose acetate. it is classified as a weak acid since it only partially dissociates in solution, but concentrated acetic acid is corrosive and can attack the skin.acetic acidnamespreferred iupac nameacetic acidsystematic iupac nameethanoic acidother namesvinegar (when dilute); hydrogen acetate; methanecarboxylic acid[1][2]identifierscas number64-19-7 3d model (jsmol)interactive image3dmetb00009 reference506007chebichebi: 15366 chemblchembl539 chemspider171 drugbankdb03166 echa infocard100.000.528ec number200-580-7e numbere260 (preservatives)gmelin reference1380iuphar/bps1058keggd00010 meshacetic+acidpubchem cid176rtecs numberaf1225000uniiq40q9n063p un number2789inchiinchi=1s/c2h4o2/c1-2(3)4/h1h3,(h,3,4) key: qtbsbxvteameqo-uhfffaoysa-n smilescc(o)=o

answered: Guest

we have been given a quadratic function $f(x)=(x-5)^{2} +2$ and we need to restrict the domain such that it becomes a one to one function.

we know that vertex of this quadratic function occurs at (5,2).

further, we know that range of this function is $[2,\infty)$ .

if we restrict the domain of this function to either $(-\infty,5]$ or $[5,\infty)$ , it will become one to one function.

let us know find its inverse.

$y=(x-5)^{2}+2$

upon interchanging x and y, we get:

$x=(y-5)^{2}+2$

let us now solve this function for y.

$(y-5)^{2}=x-2\\ y-5=\pm \sqrt{x-2}\\ y=5\pm \sqrt{x-2}\\$

hence, the inverse function would be $f^{-1}(x)=5+\sqrt{x-2}$ if we restrict the domain of original function to $[5,\infty)$ and the inverse function would be $f^{-1}(x)=5-\sqrt{x-2}$ if we restrict the domain to $(-\infty,5]$ .