A Doppler radar sends a pulse at 6.00x109 Hz. It reflects off clouds
moving away at 8.52 m/s. What is the
change in frequency in the echo?
(Unit = Hz)

come closer and become far apart and become steam/gas

dang that balls went far

= initial pressure

= final pressure = 2

= initial volume

= final volume = /4

= initial temperature = 20 c = 20 + 273 = 293 k

= final temperature = ?

using the equation

you get 2.3=1.21*\frac{a}2 or 4.6=1.21a or a=3.802 (b)

explanation: