Acar traveling 95 km/h strikes a tree. the front end of the car compresses and the driver comes to rest after traveling 0.80 m . part a what was the magnitude of the average acceleration of the driver during the collision?

The magnitude of the average acceleration of the driver during the collision is about 440 m/s²

Acceleration is rate of change of velocity.

a = acceleration ( m/s² )

v = final velocity ( m/s )

u = initial velocity ( m/s )

t = time taken ( s )

d = distance ( m )

Let us now tackle the problem !

This problem is about Kinematics.

We will solve it in the following way.

Given:

initial velocity of the car = u = 95 km/h = (475/18) m/s

distance = d = 0.80 m

final velocity of the car = v = 0 m/s

Unknown:

acceleration = a = ?

Solution:

Grade: High School

Subject: Physics

Chapter: Kinematics

Keywords: Velocity , Driver , Car , Deceleration , Acceleration , Obstacle , Speed , Time , Rate , Tree

i guess it’s a and b

grav force prop 1/r squared 2r all squared is 4rsquared 1/4rsquared quartered