Acar slows down from 28m/s to rest in a distance of 88m. what was its acceleration assumed constant?

First calculate the time by using following equation:
d= (vi+vf)/2 x t 

where t = time

vi is the initial velocity = 28 m/s

vf is the final velocity  = 0 m/s

and d is the distance covered = 88m

88 = (28 + 0)/2 x t

t = 88/14 = 6.286 s

Now use this equation to find acceleration:

a= (vf-vi)/t 

a = 0 – 28/ 6.286

The acceleration of the car was -4.4545 m/sec² where the negative sign indicates deceleration (decrease in acceleration)

Explanation:

To answer this question, we will use the following equation of motion:

v² = u² + 2as

where:

v is the final velocity = 0 m/sec (car became at rest)

u is the initial velocity = 28 m/sec

a is the acceleration we want to find

s is the distance covered = 88 m

Substitute with the givens in the equation to get "a" as follows:

v² = u² + 2as

0 = (28)² + 2(a)(88)

0 = 784 + 176a

176a = -784

= -4.4545 m/sec²

Hope this helps :)

i had this question and the answer was 3.15 miles.

martina travels from school to her mom's office. from there, she walks to school. after school, she walks to the library and then to a friends house before finally ending back at home. find martina's total distance traveled.

a) 0 miles  

b) 0.4 miles  

c) 1 mile  

d) 3.15 miles