Afurlong is an old british unit of length equal to 0.125 mi, derived from the length of a furrow in an acre of ploughed land. a fortnight is a unit of time corresponding to two weeks, or 14 days and nights. find the speed of light in mega furlongs per fortnight. (one mega furlongs equals a million furlongs.)

The speed of light is: c = 3x10^8 m/s 

or 

c = 186,000,000 miles/sec = 1.86x10^8 mi/s 

1 furlong = 0.125 mile 

1 fortnight = 2 weeks(7d/wk)(24h/d)(3600s/h) 
= 1209600s = 1.2096x10^6 s 

Therefore, 

c =1.86x10^8 mi/s(1furl/0.125mi)(1.2096x10^6s/fort) 

c = 18x10^14 furlong/fortnight = 18x10^8 Mfurlong/fortnight

hi there!

your question asks at which segment does freezing occur.

since we're talking about water, the freezing point of water will be 32 degrees fahrenheit or below.

hope this ! ~

double the distance = divide strength by 4