What is the temperature change in 355 ml of water upon absorption of 34 kj of heat? (the specific heat capacity of water is 4.184 j/g∘c.) express your answer in degrees celsius?

Heat gained or absorbed in a system can be calculated by multiplying the given mass to the specific heat capacity of the substance and the temperature difference. It is expressed as follows:

Heat = mC(T2-T1)

We have to determine the value of (T2-T1) which is the temperature change. To do this, we simply substitute the values given above. We do as follows:

Heat = mC(T2-T1)

34 kJ ( 1000 J / kJ ) = 355 mL ( 1 g / mL ) (4.184 J / g-C ) (T2-T1)

(T2-T1) = 22.89 degrees Celsius or Kelvin

THerefore, the temperature change of the abosrption of 34 kJ of heat by water would be 22.89 degrees Celsius.