The magnitude of the electric force between two protons is 2.3x10-26 n. how far apart are they?
a. 0.022

To solve this problem, we make use of the Coulumb’s law which relates the electrical force to the charges. The formula used in Coulumb’s law is given as:

F = k q1 q2 / r^2

where,

F = electric force = 2.3 *  10^-26 N

k = Coulumb’s constant = 9 * 10^9 N m^2/C^2

q1 = q2 = electric charge of protons = 1.602 * 10^-19 C

r = distance between the two protons

Substituting the given values:

2.3 *  10^-26 N = (9 * 10^9 N m^2/C^2) (1.602 * 10^-19 C)^2 / r^2

r^2 = 0.01 m^2

r = 0.1 m

Therefore the protons are only 0.1 m apart or 10 cm.

a displacement distance is size of displ

distance = 150m

displ = root (50 ^2 + 100^2)

root(2500+10000)

root 125000