Acar starts from rest and accelerates at a constant rate in a straight line. in the first second the car covers a distance of 2.0 meters. how fast will the car be moving at the end of the second second?

The solution would be like this for this specific problem:

Given:

Distance = 2.0 meters

Find:

Vx = ?

 

Δx =

 

a = 2 Δx 

 

 

Therefore, the car will be moving 8 m/s at the end of the second second.

To add, the physical vector quantity that both requires magnitude and direction is called velocity. It is also equivalent to a direction of motion and specification of its speed.

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Distance covered = speed x timethe distance traveled going against the stream = distance traveled with the stream.therefore it is the speed and the time that are the variables.as he travels the same distance both ways, speed x time is the same for each way.going upstream his speed is 4 kph; going downstream his speed is 6 kph.therefore we have two simultaneous equations: time upstream x 4 = time downstream x 6time upstream + time downstream = 60 minutestherefore we have the equation: time upstream = 6/10 hour, time downstream therefore = 4/10 hour.distance traveled at 4km/hr in 6/10 hour = 24/10 = 2.4km.check: distance traveled at 6km/hr in 4/10 hour = 24/10 = 2.4km.