Abird experiences an acceleration of -1.80 m/s^2 for 3.81 s, and ends up 26.5 m to the left of its starting point. what is its final velocity?

To solve this problem, we can assume that the motion is linear so that we can use the equations:

Xf = Xi + v0 t + 0.5 a t^2                  ---> 1

vf = v0 + a t                                         ---> 2

where Xi = initial distance = 0, v0 = initial velocity, Xf = final distance = 26.5 m, a = acceleration = - 1.80 m/s^2, t = time = 3.81 s, vf = final velocity

 

Substituting the given values into equation 1 to find for v0:

26.5 = v0 (3.81) + 0.5 (-1.80 m/s^2) (3.81)^2

3.81 v0 = 39.56449

v0 = 10.38 m/s

 

Using equation 2 to find for vf:

vf = 10.38 + (-1.80) (3.81)

vf = 3.53 m/s

Is a  vector quantity  that refers to "the rate at which an object changes its position." imagine a person moving rapidly - one step forward and one step back - always returning to the original starting position. while this might result in a frenzy of activity, it would result in a zero velocity. because the person always returns to the original position, the motion would never result in a change in position. since velocity is defined as the rate at which the position changes, this motion results in zero velocity. if a person in motion wishes to maximize their velocity, then that person must make every effort to maximize the amount that they are displaced from their original position. every step must go into moving that person further from where he or she started. for certain, the person should never change directions and begin to return to the starting position.