Abullet is fired horizontally with an initial velocity of 144.7 m/s from a tower 11 m high. if air resistance is negligible, what is the horizontal distance the bullet travels before hitting the ground?

H = 11 m, the vertical distance that the bullet falls.
Initial vertical velocity  = 0
Horizontal velocity  = 144.7 m/s

The time, t, taken to fall 11 m is given by
(1/2)*(9.8 m/s²)*(t s)² = (11 m)
4.9t² = 11
t = 1.4983 s

If aerodynamic resistance is ignored, the horizontal distance traveled before the bullet hits the ground is
d = (144.7 m/s)*(1.4983 s) = 216.8 m

216.8 m

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My answer is opptionc, just check with anyone else