To what temperature would you have to heat a brass rod for it to be 1.8 % longer than it is at 30 ∘c?

We have to heat a brass rod at 982.4 for it to be 1.8 % longer than it is at 30.

Given :

Brass rod is 1.8 % longer than it is at 30.

Solution :

We know that,

     ---- (1)

Where, is the elongation,

is the original length,

is the coefficient of linear expansion. For brass,

,

is the change in temperature.

1.8 % length expansion means:

Now put the values of

    in equation (1) we get:

We have to heat a brass rod at 982.4 for it to be 1.8 % longer than it is at 30.

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weather forecasts are done by collecting data about the current state of the atmosphere mainly the temperature, humidity and wind and using meteorology, to determine the atmosphere that evolves over time. the h and l mean the high and low pressure. the red strip is a warm front. the blue strip is a cold front. the blue and red strip is a stationary front. the purple strip is a occluded front.

explanation:

beta is electron from nucleus

something from nucleus has changed, but charge must be same for cons of charge