Two person a and b of weight 60kg and 40kg respectively stand facing each other, and pull on a light rope streched between them. find the ratio of distance covered by them when they meet if their intial separation was 5 metre

To be able to successfully pull the rope with balance, the work done by person A should be just equal to the work done by person B.

workA = workB  > 1

Where: work = force * distance

In this case, force = mass * gravity

So work = mass * gravity * distance

Rewriting equation 1:

massA * gravity * distanceA = massB * gravity * distanceB  >2

We know that distanceA + distanceB = 5 m, therefore distanceA = 5 – distanceB. Substituting this to equation 2 and cancelling constant g:

massA * distanceA = massB * distanceB

60 kg * (5 – distanceB) = 40 kg * distanceB

distanceB = 3 m

distanceA = 5 – distanceB = 2 m

ratio is: distanceA / distanceB = 2/3 = 0.67

well, you would divide 135 by 33 to get your answer. then that is how many seconds it would take. boardman should fly about 132 m or 4.090909090909091 seconds.

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