Asky diver steps from a high-flying helicopter. if there were not air resistance, how fast would she be falling at the end of a 12 second jump?

If there is no air resistance and the body, in this case the sky diver simply falls from the helicopter then, the motion can be described as a free-falling body. The equation that would allow us to determine the speed of the body at any time, t is,

                                    v(t)  = vo + gt

where v(t) is the unknown velocity, vo is the initial velocity which is equal to zero and g is the acceleration due to gravity which is equal to 9.8 m/s2.

Substituting the known values,

                                    v(t) = 0 + (9.8 m/s2)(12s)

                                                v(t) = 117.6 m/s

Hence, the speed of the sky diver at the end of 12 second is approximately 117.6 m/s.  

the moon affects the earth gravitation ally, causing certain motions of that body and also producing tides in its ocean and atmosphere. the tidal wave in our atmosphere is, however, far too minute to be an effective cause in any known meteorological phenomenon.

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