You throw a ball at 37° above the horizontal and you want to hit a target on the ground, 20 ft from where you are standing. how fast should you throw the ball? what will be its final velocity?

Let the launch velocity be V ft/s.

The horizontal component of velocity is
Vx = Vcos(37) = 0.7986V ft/s

The vertical component of velocity is
Vy = Vsin(37) = 0.6018V ft/s

The time, t, to reach maximum height is determined by
0 = Vy - gt0 = (0.6018V ft/s) - (32.174 ft/s^2)(t s)
0 = 0.6018V - 32.174t
t = (0.6018V)/32.174 = 0.0187V s

The time to travel 20 ft horizontally takes a time of 2t. Therefore
Vx*(2t) = 20
(0.7986V)*(2*0.0187V) = 20
0.0299V^2 = 20
V^2 = 668.8963
V = 25.86 ft/s

The final velocity will have components (Vx,  Vy). Its magnitude will be V or 25.86 ft/s.

V = 25.9 ft/s (nearest tenth)

The answer is water molecules are split.cellular respiration and photosynthesis are complement  reactions to each other. these are reverse reactions. in cellular respiration glucose and oxygen yield water and carbon dioxide. so, when respiration begins,  glucose molecules are split. in the opposite reaction - in photosynthesis, carbon dioxide and water yield glucose and oxygen. thus,  when respiration begins, water molecules are split.