Physics, 30.10.2019 03:31, emm3456

Suppose a 60.0-kg gymnast climbs a rope. (a) what is the tension in the rope if he climbs at a constant speed? (

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answered: njorda7211

The tension in the rope when gymnast climbs a rope with constant speed will be \boxed{588{\text{ N}}}.

Further explanation:

We have to calculate the tension in the rope when the gymnast climbs a rope with the constant speed.

Given:

We have given that,

The mass of the gymnast is $60{\text{ kg}}$ .

Formula and concept used:

Consider a body is moving with an acceleration in upward direction, then the direction of the inertia force will be in the opposite direction of the direction of the acceleration.

That is, the direction of the inertia force will be in the downward direction for the moving body.

Inertia force can be calculated as,

$\boxed{{F_I}=ma}$

Here, ${F_I}$ is the inertia force and is the acceleration.

So, the net downward force will be equal to the sum of the weight of the body and the inertia force.

$\boxed{F=W + {F_I}}$

Substitute the values of as and ${F_I}$ as in above equation.

$\boxed{F=mg + ma}$ …… (1)

Here, gymnast is climbing with the constant speed.

So, acceleration of the gymnast in upward direction will be zero.

Substitute for in equation (1).

So, the net downward force will be,

F = mg

This downward force will be balanced by the tension in the rope.

So, tension in the rope will be,

$\boxed{T = mg}$ …… (2)

Calculation:

Substitute the value $60{\text{ kg}}$ for and $9.8{\text{ }}{{\text{m}} \mathord{\left/ {\vphantom {{\text{m}} {{{\text{s}}^2}}}} \right. \kern-\nulldelimiterspace} {{{\text{s}}^2}}}$ for in equation (2).

$\begin{aligned}T&=60\times9.8\\&=588{\text{N}}\\\end{aligned}$

So, the tension in the rope will be $\boxed{588{\text{ N}}}$ .

Learn more:

1. Type of mirror used by dentist:

2. Wind and solar energy:

3. Motion under force .

Answer details:

Grade: High School

Subject: Physics

Chapter: Force

Keywords:

Astronaut, climb a rope, tension in the rope, constant speed, acceleration, acceleration due to gravity, force, weight, mass, downward, upward, direction, motion.

Suppose a 60.0-kg gymnast climbs a rope. (a) what is the tension in the rope if he climbs at a const

answered: Guest

car stops. he keeps going = he has inertia

answered: Guest

the grams of oxygen gas that can be produced is 20.6 grams of o₂

calculation

2liclo₃ → 2 licl + 3 o₂

step 1: find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5 +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281 moles

step 2: use the mole ratio to calculate the moles of o2

from equation above, liclo₃: o₂ is 2: 3

therefore the moles of o₂=0.4281 moles x3/2 =0.6422 moles

step 3: find mass of o₂

mass= moles x molar mass

from periodic table the molar mass of o₂ = 16 x2= 32 g/mol

mass=0.6422 moles x 32 g/mol = 20.6 grams of o₂

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Suppose a 60.0-kg gymnast climbs a rope. (a) what is the tension in the rope if he climbs at a const...