Agolf club exerts an average force of 1000 n on a 0.045-kg golf ball which is initially at rest. the club is in contact with the ball for 1.8 ms. what is the speed of the golf ball as it leaves the tee?

From Newton's Second Law of motion, force (F) is the product of mass (m) of the object and the acceleration (a).

                          F = m x a
Substituting the known values above,
                    1000 N = (0.045 kg) x a

                              a = 22222.22 m/s²

Velocity, on the other hand, is the product of acceleration and time.
                             v = a x t
Substituting the known values,
                             v = (22222.22 m/s²)(1.8 x 10^-3 s)
                                        v = 40 m/s

Thus, the velocity or speed of the golf ball is 40 m/s. 

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