The latent heat of fusion of mercury is 11.8 j/g. the amount of energy, rounded to the nearest tenth, needed to change 8.00 grams of mercury to a liquid .

Given:

latent heat of fusion of mercury = 11.8 J/g.
Amount of mercury = 8 g

Required:

Energy required to change 8 g of mercury to liquid.

Solution:

Since we already know the amount of heat needed for every gram of mercury which is 11.8 J/g. We multiply the amount to get the energy.

Energy required to change 8 g of mercury to liquid = 11.8 J/ g × 8 g
Energy required to change 8 g of mercury to liquid = 94.4 J

Pe = 1/2k(x)^2  and .05n/m = .05x10^-9m = x