Physics, 01.10.2019 19:50, mgaud2786

Which describes how the spring constant affects the potential energy of an object for a given displacement from an equilibrium position?
a.)the higher the spring constant, the greater the gravitational potential energy.
b.)the lower the spring constant, the greater the gravitational potential energy.
c.)the higher the spring constant, the greater the elastic potential energy.
d.)the lower the spring constant, the greater the elastic potential energy.

Answers: 2

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answered: PatienceJoy

The correct answer to the question is : C) The higher the spring constant, the greater the elastic potential energy.

EXPLANATION:

Before going to answer this question, first we have to understand the potential energy.

The potential energy of a body is defined as the energy gained by the body due to its position or change in configuration.

The potential energy of a body due to its position from the surface of earth is known as gravitational potential energy. The potential energy gained by the body due to its change in configuration is known as elastic potential energy.

Hence, in case of spring, the potential energy is elastic in nature as there is change in configuration.

The elastic potential energy of a spring having spring constant k and stretched to a distance x from the equilibrium position is calculated as-

Elastic potential energy P.E = $\frac{1}{2}kx^2$ .

Hence, more is the spring constant, more is the elastic potential energy.

answered: Guest

total distance travelled = 60 miles

total time taken =1.5 hours

average speed = total distance / total time

60 / 1.5

= 40

therefore, average speed = 40 m/h

happy to

pls mark as brainliest

answered: Guest

answer: the correct answer is 1.

explanation: there are various process in which a radioactive nuclei decays:

1) alpha decay: in this process, a heavier nuclei decays into lighter nuclei by releasing alpha particle. the mass number is reduced by 4 units.

$_a^z\textrm{x}\rightarrow _{a-2}^{z-4}+_2^4\alpha$

2) electron capture: in this decay process, a parent nuclei absorbs an electron and gets converted into a neutron. simply, a proton and an electron combines together to form a neutron. mass number does not change in this process.

$_a^z\textrm{x}+_{-1}^0\textrm{e}\rightarrow _{z-1}^a\textrm{y}$

3) gamma ray emission: it is a decay process in which an unstable nuclei gives excess energy by a spontaneous electromagnetic process. this decay releases $\gamma -radiations$ . this process does not change the mass number.

$_a^z\textrm{x}^*\rightarrow _a^z\textrm{x}+_0^0\gamma$

4) positron emission: it is a type of decay process, in which a proton gets converted to neutron and an electron neutrino. this is also known as $\beta ^+$ -decay. in this the mass number remains same.

$_a^z\textrm{x}\rightarrow _{z-1}^a\textrm{y}+_{+1}^0e$

from the above information, we see that only alpha-decay is producing a change in the mass number of the nucleus.

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Which describes how the spring constant affects the potential energy of an object for a given displa...