What work is done by a system on its environment when an ideal gas is maintained at a constant pressure of 200 newtons/meter2 during an isobaric process, while the volume decreases by 0.2 cubic meters?

The correct answer to the question is : 40 J.

EXPLANATION:

As per the question, the volume of gas is decreased under isobaric process.

The pressure of the gas is given as P = .

The volume of decrease of the gas is given as dV = 0.2 cubic metre

                                                                                    =

We are asked to calculate the work done by the system.

The work done by the system is calculated as -

                               Work done W = P × dV

                                                       =

                                                       = 40 J.

We know that work done by the body is positive.

Hence, the work done by the system is 40 J.