Abaseball thrown from the outfield is released from shoulder height at an initial velocity of 29.4 m/s at an initial angle of 30.0 with respect to the horizontal. what is the maximum vertical displacement that the ball reaches during its trajectory?

22.05 meters

Explanation:

In order to get the answer, basically it is a distance we are looking for.

We are going to get familiar with the formula of displacement:

Δx

of the angle of 30°

that is

average velocity

Now

Δ\\ because the baseball goes the opposite direction when is going down until it gets to the grown. Then

and using this formula

we divide both sides by and we get

Finally 3 seconds is the time in motion, so we divide by two because we just need the time going up, that happens to be the same time going down.

time in motion

Δx

a

explanation:

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