Aproton is moved so that its electric potential energy increases from 2.0 × 10-18 j to 6.0 × 10-18 j. the magnitude of the charge on a proton is 1.602 × 10-19 c.

the electric potential difference through which the proton moved, to the nearest whole number, is

Answer : The electric potential difference through which the proton moved, to the nearest whole number is, 25 V

Solution :

Potential difference : It is defined as the work done by the unit charge.

Formula used :

where,

= electric potential difference

= electric potential energy

q = charge on  proton

Now put all the given values in the above formula, we get the value of electric potential difference.

Therefore, the electric potential difference through which the proton moved, to the nearest whole number is, 25 V

answer: the rock sample is a sedimentary rock.

explanation:

it is given that:

mass of rock sample, m = 2.7 g

volume of rock sample,

so, density of rock sample will be

since, the density of rock sample is . hence, the rock sample is a sedimentary rock, whose densities varies between .