As the distance between a satellite in a circular orbit and the central object increases, the period of the satellite .

a. increases
b. decreases
c. continuously fluctuates
d. stays the same

A. increases

Explanation:

We can answer the question by reminding Kepler's third law, which states that

"for an object in motion around a central object (such as a satellite in orbit around a planet), the cube of the distance between the satellite and the centre of the orbit is proportional to the square of its orbital period"

In formula, this can be written as

where r is the distance between the satellite and the central object while T is the orbital period of the satellite. From this relationship, we see that if r (the distance) increases, then the period of the satellite (T) increases as well.

i guess it’s a and b

it is a negative acceleration