Aski lift is used to transport people from the base of a hill to the top. if the lift leaves the base at a velocity of 15.5 m/s and arrives at the top with a final velocity of 0 m/s, what is the height of the hill? round the answer to the nearest tenth

This can be calculated with the law of conservation of energy. The sky lift is starting with the speed v= 15.5 m/s and all of it's kinetic energy Ek is transformed to potential energy Ep so the energies have to be equal: Ep=Ek.
Since Ek=(1/2)*m*v² where m is mass and v is the speed, Ep=m*g*h, where m is mass, g= 9.81 m/s² and h is height. Now:

Ek=Ep 

(1/2)*m*v²=m*g*h, masses cancel out,

(1/2)*v²=g*h, divide by g to get the height,

(1/2*g)*v²=h and now plug in the numbers:

h=12.245 m. Height of the hill rounded to the nearest tenth is h=12.25 m 

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