1. an 800.0 kg roller coaster car is at rest at the top of a 95 m hill. it rolls down the first drop to a height of 31 m. when it travels to the top of the second hill, it is moving at 28 m/s. it then rolls down the second hill until it is at ground level. draw a picture of the roller coaster drop and calculate the kinetic and potential energy at the top and bottom of each hill.

At the top of first hill

K = 0

U = 744800

At the top of second hill

U = 243040 J

K = 313600 J

At the bottom of the hill

K = 0

Explanation:

potential energy is given by

U = mgH

and kinetic energy is given by

now we have initial potential energy at the top of the hill is given as

we have initial potential energy at the top of the second hill is given as

we have initial potential energy at the bottom of the hill is given as

explanation:

an enlarged virtual image is the answer