6. jim wishes to push a 100. n wood crate across a wood floor. what is the minimum horizontal force that would be required to start the crate moving?

50 N

Explanation:

The minimum horizontal force required to start the crate moving must be equal to the maximum force of static friction that acts between the floor and the crate.

The maximum force of static friction is given by:

where

is the coefficient of static friction

is the normal reaction exerted by the floor on the crate.

For wood-wood, as in this case, the maximum coefficient of static friction is about .

For a horizontal surface, the normal reaction is equal to the weight of the object, so in this case . Therefore, the minimum horizontal force required will be:

answer: point c: b. 1/2 potential, 1/2 kinetic, point a: 3/4 of its potential energy, point d or b: 3/4 potential, 1/4 kinetic

explanation: i cant explain. it's difficult to explain.

jupiter is the largest planet in our solar system, having a mass and radius that are respectively, 318 and 11.2 times that of earth. suppose that an object falls from rest near the surface of each planet and that the acceleration due to gravity remains constant during the fall. each object falls the same distance before striking the ground. determine the ratio of the time of fall on jupiter to that on earth.